3t(t+4)-15=t(t+2)+2t^2

Solution for 3t(t+4)-15=t(t+2)+2t^2 equation:

3t(t+4)-15=t(t+2)+2t^2

We move all terms to the left:

3t(t+4)-15-(t(t+2)+2t^2)=0

We multiply parentheses

-(t(t+2)+2t^2)+3t^2+12t-15=0


We calculate terms in parentheses: -(t(t+2)+2t^2), so:

t(t+2)+2t^2

determiningTheFunctionDomain
2t^2+t(t+2)

We multiply parentheses

2t^2+t^2+2t

We add all the numbers together, and all the variables

3t^2+2t

Back to the equation:

-(3t^2+2t)


We add all the numbers together, and all the variables

3t^2+12t-(3t^2+2t)-15=0

We get rid of parentheses

3t^2-3t^2+12t-2t-15=0

We add all the numbers together, and all the variables

10t-15=0

We move all terms containing t to the left, all other terms to the right

10t=15

t=15/10

t=1+1/2